Q1.When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l). The elastic potential energy stored in the extended wire is:
- AMgl
- BMgL
- C½ MglAnswer
- D½ MgL
The stretching force grows linearly from zero to Mg as the wire extends, so the energy stored is the area under the force-extension line, not force times extension. Elastic potential energy = ½ × (maximum force) × (extension) = ½ Mgl. The extension is l, the extra length, not the original length L, which is why MgL and ½ MgL are wrong. Mgl is the work done by gravity; half of it is stored in the wire.
Source: NEET 2019 (5 May), Code P1, Q1