Chemical Thermodynamics

15 NEET questions on Chemical Thermodynamics. A sample is shown below with full explanations; the rest are available free after signing up.

Chemical Thermodynamics2026hard

Q1.Two moles of an ideal gas undergo free expansion from 10 L to 100 L at 300 K. The values of ΔSsystem and ΔSsurroundings are (R is the universal gas constant)

  • AΔSsystem = 0; ΔSsurroundings = 0
  • BΔSsystem = 4.606 R; ΔSsurroundings = −4.606 R
  • CΔSsystem = 0; ΔSsurroundings = 4.606 R
  • DΔSsystem = 4.606 R; ΔSsurroundings = 0Answer

Explanation

Entropy is a state function, so the system's change is the same as for a reversible isothermal expansion: ΔS = nR ln(V₂/V₁) = 2R ln 10 = 4.606R. But free expansion is into a vacuum, so no heat crosses the boundary and the surroundings are left completely unchanged: ΔSsurroundings = 0. The total is positive, as an irreversible process requires.

Source: NEET 2026 re-exam (21 June), Code 50, Q59

Chemical Thermodynamics2026medium

Q2.A protein undergoes reversible thermal denaturation from its initial state N to denatured state D according to N ⇌ D. At 60 °C, the concentrations of both N and D are equal at equilibrium, and the standard enthalpy change of denaturation is 666 kJ mol⁻¹. The standard entropy change (ΔS° in kJ K⁻¹ mol⁻¹) of the protein upon denaturation at 60 °C is closest to

  • A2.0Answer
  • B2000.0
  • C333.0
  • D11.1

Explanation

Equal concentrations at equilibrium means K = 1, so ΔG° = −RT ln K = 0. With ΔG° = ΔH° − TΔS° = 0 the entropy change is simply ΔH°/T, and T must be in kelvin: 666/333 = 2.0 kJ K⁻¹ mol⁻¹.

Source: NEET 2026 re-exam (21 June), Code 50, Q74

Chemical Thermodynamics2025hard

Q3.The standard heat of formation, in kcal/mol, of Ba²⁺ is [Given: standard heat of formation of SO₄²⁻ ion (aq) = −216 kcal/mol, standard heat of crystallisation of BaSO₄(s) = −4.5 kcal/mol, standard heat of formation of BaSO₄(s) = −349 kcal/mol]

  • A−128.5Answer
  • B−133.0
  • C+133.0
  • D+220.5

Explanation

Build the target equation by Hess’s law. Formation of solid BaSO₄ from its elements is −349 kcal/mol. That can be split into forming the two aqueous ions and then crystallising them, so ΔH_f(BaSO₄) = ΔH_f(Ba²⁺) + ΔH_f(SO₄²⁻) + ΔH_crystallisation. Substituting, −349 = ΔH_f(Ba²⁺) + (−216) + (−4.5), so ΔH_f(Ba²⁺) = −349 + 216 + 4.5 = −128.5 kcal/mol.

Source: NEET 2025 (4 May), Code 45, Q85

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