Q1.The correct order of solubility of the given salts in water at 298 K is
- 1.AgBr — Ksp at 298 K = 5.0 × 10⁻¹³
- 2.Zn(OH)₂ — Ksp at 298 K = 1.0 × 10⁻¹⁵
- 3.Hg₂Cl₂ — Ksp at 298 K = 1.3 × 10⁻¹⁸
- AHg₂Cl₂ > Zn(OH)₂ > AgBr
- BAgBr > Zn(OH)₂ > Hg₂Cl₂
- CHg₂Cl₂ > AgBr > Zn(OH)₂
- DZn(OH)₂ > AgBr > Hg₂Cl₂Answer
Ksp values cannot be compared directly across salts of different stoichiometry — that is the whole trap. AgBr is AB type, so S = √Ksp ≈ 7.1 × 10⁻⁷. Zn(OH)₂ and Hg₂Cl₂ are AB₂ type with Ksp = 4S³, giving S ≈ 6.3 × 10⁻⁶ and 6.9 × 10⁻⁷. So Zn(OH)₂ is the most soluble despite having a smaller Ksp than AgBr.
Source: NEET 2026 re-exam (21 June), Code 50, Q52