Kinetic Theory of Gases

11 NEET questions on Kinetic Theory of Gases. A sample is shown below with full explanations; the rest are available free after signing up.

Kinetic Theory of Gases2025medium

Q1.An oxygen cylinder of volume 30 litre has 18.20 moles of oxygen. After some oxygen is withdrawn from the cylinder, its gauge pressure drops to 11 atmospheric pressure at temperature 27 °C. The mass of the oxygen withdrawn from the cylinder is nearly equal to: [Given, R = 100/12 J mol⁻¹ K⁻¹, molecular mass of O₂ = 32, and 1 atm pressure = 1.01 x 10⁵ N m⁻²]

  • A0.125 kg
  • B0.144 kg
  • C0.116 kgAnswer
  • D0.156 kg

Explanation

Gauge pressure is measured above atmospheric, so the absolute pressure is 11 + 1 = 12 atm — missing this is the usual error here. Then n = PV/RT = (12 x 1.01 x 10⁵ x 30 x 10⁻³)/((100/12) x 300) ≈ 14.54 mol, so (18.20 − 14.54) x 32 g ≈ 0.116 kg was withdrawn.

Source: NEET 2025 (4 May), Code 45, Q14

Kinetic Theory of Gases2025medium

Q2.A container has two chambers of volumes V₁ = 2 litres and V₂ = 3 litres separated by a partition made of a thermal insulator. The chambers contain n₁ = 5 and n₂ = 4 moles of ideal gas at pressures p₁ = 1 atm and p₂ = 2 atm, respectively. When the partition is removed, the mixture attains an equilibrium pressure of

  • A1.3 atm
  • B1.6 atmAnswer
  • C1.4 atm
  • D1.8 atm

Explanation

The container is insulated, so the total internal energy is unchanged. Since U is proportional to PV for an ideal gas, this reduces to P(V₁ + V₂) = P₁V₁ + P₂V₂, giving P = (1 x 2 + 2 x 3)/5 = 1.6 atm — and note the mole counts are not needed at all.

Source: NEET 2025 (4 May), Code 45, Q29

Kinetic Theory of Gases2026medium

Q3.The mean free path of molecules in an ideal gas A is half that of another ideal gas B. The diameter of the spherical molecules of gas A is twice the diameter of the molecules of B. If number densities of the gases A and B are nA and nB, respectively, the correct option is:

  • AnA = nB
  • BnA = 2nB
  • CnA = (1/4) nB
  • DnA = (1/2) nBAnswer

Explanation

The mean free path is λ = 1/(√2 π d² n), so λ is inversely proportional to d²n. Halving λ means doubling the product d²n — but doubling the diameter has already multiplied d² by four, so the number density must fall by a factor of two, giving nA = nB/2.

Source: NEET 2026 re-exam (21 June), Code 50, Q2

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