Q1.An oxygen cylinder of volume 30 litre has 18.20 moles of oxygen. After some oxygen is withdrawn from the cylinder, its gauge pressure drops to 11 atmospheric pressure at temperature 27 °C. The mass of the oxygen withdrawn from the cylinder is nearly equal to: [Given, R = 100/12 J mol⁻¹ K⁻¹, molecular mass of O₂ = 32, and 1 atm pressure = 1.01 x 10⁵ N m⁻²]
- A0.125 kg
- B0.144 kg
- C0.116 kgAnswer
- D0.156 kg
Gauge pressure is measured above atmospheric, so the absolute pressure is 11 + 1 = 12 atm — missing this is the usual error here. Then n = PV/RT = (12 x 1.01 x 10⁵ x 30 x 10⁻³)/((100/12) x 300) ≈ 14.54 mol, so (18.20 − 14.54) x 32 g ≈ 0.116 kg was withdrawn.
Source: NEET 2025 (4 May), Code 45, Q14