Q1.In some appropriate units, time (t) and position (x) relation of a moving particle is given by t = x² + x. The acceleration of the particle is
- A−2/(x + 2)³
- B−2/(2x + 1)³Answer
- C+2/(x + 1)³
- D2/(2x + 1)
Differentiating t = x² + x with respect to x gives dt/dx = 2x + 1, so the velocity is v = dx/dt = 1/(2x + 1). Acceleration then follows from a = v dv/dx = (2x + 1)⁻¹ x [−2(2x + 1)⁻²] = −2/(2x + 1)³.
Source: NEET 2025 (4 May), Code 45, Q15