Q1.2A → B is a zero-order reaction, where k = 1.0 mol L⁻¹ min⁻¹. If the initial concentration of A is 2 M, then the time taken to complete 75% of the reaction will be
- A1.5 min
- B0.75 minAnswer
- C1.0 min
- D2.0 min
For zero order the rate is constant, and with the stoichiometric coefficient 2 the rate law is −(1/2)d[A]/dt = k, so ([A]₀ − [A]t) = 2kt. Completing 75% of the reaction leaves [A]t = 0.5 M, giving t = (2 − 0.5)/(2 × 1.0) = 0.75 min. Forgetting the factor of 2 is the usual slip here.
Source: NEET 2026 re-exam (21 June), Code 50, Q60