Q1.The electric field in a plane electromagnetic wave is given by Ez = 60 cos(5x + 1.5 x 10⁹ t) V/m. Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field):
- ABy = 2 x 10⁻⁷ cos(5x + 1.5 x 10⁹ t) TAnswer
- BBx = 2 x 10⁻⁷ cos(5x + 1.5 x 10⁹ t) T
- CBz = 60 cos(5x + 1.5 x 10⁹ t) T
- DBy = 60 sin(5x + 1.5 x 10⁹ t) T
In a plane electromagnetic wave E and B oscillate in phase with amplitudes related by B₀ = E₀/c, so B₀ = 60/(3 x 10⁸) = 2 x 10⁻⁷ T. E points along z and the wave travels along −x, so B must lie along y — which rules out the other three options.
Source: NEET 2025 (4 May), Code 45, Q9