Q1.A microscope has an objective of focal length 2 cm, eyepiece of focal length 4 cm and the tube length of 40 cm. If the distance of distinct vision of eye is 25 cm, the magnification in the microscope is
- A100
- B125Answer
- C150
- D250
For a compound microscope with the final image at the near point, M = (L/f_o) x (D/f_e), where L is the tube length. Substituting L = 40 cm, f_o = 2 cm, D = 25 cm and f_e = 4 cm gives M = 20 x 6.25 = 125.
Source: NEET 2025 (4 May), Code 45, Q2