Magnetic Effects of Current and Magnetism

16 NEET questions on Magnetic Effects of Current and Magnetism. A sample is shown below with full explanations; the rest are available free after signing up.

Magnetic Effects of Current and Magnetism2025medium

Q1.An electron (mass 9 x 10⁻³¹ kg and charge 1.6 x 10⁻¹⁹ C) moving with speed c/100 (c = speed of light) is injected into a magnetic field B of magnitude 9 x 10⁻⁴ T perpendicular to its direction of motion. We wish to apply an uniform electric field E together with the magnetic field so that the electron does not deflect from its path. Then (speed of light c = 3 x 10⁸ m s⁻¹)

  • AE is perpendicular to B and its magnitude is 27 x 10⁴ V m⁻¹
  • BE is perpendicular to B and its magnitude is 27 x 10² V m⁻¹Answer
  • CE is parallel to B and its magnitude is 27 x 10² V m⁻¹
  • DE is parallel to B and its magnitude is 27 x 10⁴ V m⁻¹

Explanation

This is a velocity selector: the electron passes undeflected only when the electric force qE exactly cancels the magnetic force qv x B, which forces E to be perpendicular to both v and B. Equating magnitudes, E = vB = (3 x 10⁶)(9 x 10⁻⁴) = 27 x 10² V m⁻¹.

Source: NEET 2025 (4 May), Code 45, Q3

Magnetic Effects of Current and Magnetism2025easy

Q2.A 2 amp current is flowing through two different small circular copper coils having radii ratio 1 : 2. The ratio of their respective magnetic moments will be

  • A1 : 4Answer
  • B1 : 2
  • C2 : 1
  • D4 : 1

Explanation

The magnetic moment of a current loop is M = IA. The current is the same in both coils, so M is proportional to the area πr², and squaring the radius ratio 1 : 2 gives a moment ratio of 1 : 4.

Source: NEET 2025 (4 May), Code 45, Q12

Magnetic Effects of Current and Magnetism2025hard

Q3.A model for quantized motion of an electron in a uniform magnetic field B states that the flux passing through the orbit of the electron is n(h/e) where n is an integer, h is Planck's constant and e is the magnitude of electron's charge. According to the model, the magnetic moment of an electron in its lowest energy state will be (m is the mass of the electron)

  • Ahe/πm
  • Bhe/2πmAnswer
  • CheB/πm
  • DheB/2πm

Explanation

An orbiting electron is a current loop of moment μ = evr/2, and the magnetic force supplies the centripetal force so v = eBr/m, giving μ = e²Br²/2m. The quantisation rule Bπr² = nh/e fixes Br² = nh/eπ, so μ = neh/2πm, which is he/2πm in the lowest state n = 1.

Source: NEET 2025 (4 May), Code 45, Q18

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Questions are reformatted from NEET previous year papers with original explanations and topic tagging. NEET Prep is not affiliated with the NEET examining body.