Q1.Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least division in the M.S. is 0.1 cm and the zero of V.S. is at x = 0.1 cm when the jaws of Vernier callipers are closed. If the main scale reading for the diameter is M = 5 cm and the number of coinciding vernier division is 8, the measured diameter after zero error correction, is
- A5.18 cm
- B5.08 cm
- C4.98 cmAnswer
- D5.00 cm
The least count is 1 MSD − 1 VSD = 0.1 x (1 − 9/10) = 0.01 cm, so the observed reading is 5 + 8 x 0.01 = 5.08 cm. The jaws read +0.1 cm when closed, a positive zero error that must be subtracted, leaving 4.98 cm.
Source: NEET 2025 (4 May), Code 45, Q25