Organic Chemistry — Basic Principles

11 NEET questions on Organic Chemistry — Basic Principles. A sample is shown below with full explanations; the rest are available free after signing up.

Organic Chemistry — Basic Principles2026medium

Q1.The amino acid that gives a red-blood colour on treating its sodium fusion extract with sodium nitroprusside is

  • Aleucine
  • Bthreonine
  • CmethionineAnswer
  • Dserine

Explanation

Sodium nitroprusside gives a blood-red colour with sulphide ion, so the test is really a test for sulphur in the sodium fusion extract. Of the four, only methionine contains sulphur — leucine, threonine and serine do not.

Source: NEET 2026 re-exam (21 June), Code 50, Q55

Organic Chemistry — Basic Principles2026medium

Q2.Arrange the following compounds in the increasing order of polarity. Choose the correct answer from the options given below.

  • A. CH₃CH₂OCH₂CH₃
  • B. CH₃CH₂OH
  • C. CH₃COCH₃
  • D. CH₃COOH.
  • AA < B < C < D
  • BC < A < D < B
  • CC < A < B < D
  • DA < C < B < DAnswer

Explanation

The ether is least polar — two alkyl groups flanking oxygen and no hydrogen bonding of its own. The ketone's carbonyl is more polar than that. The alcohol beats both because its O-H donates hydrogen bonds, and the carboxylic acid is the most polar of all, combining a carbonyl with an O-H. So A < C < B < D.

Source: NEET 2026 re-exam (21 June), Code 50, Q89

Organic Chemistry — Basic Principles2025medium

Q3.Which one of the following compounds can exist as cis-trans isomers?

  • APent-1-ene
  • B2-Methylhex-2-ene
  • C1,1-Dimethylcyclopropane
  • D1,2-DimethylcyclohexaneAnswer

Explanation

Cis-trans isomerism needs restricted rotation plus two different groups on each of the two restricted centres. Pent-1-ene is a terminal alkene, so one doubly bonded carbon carries two hydrogens. 2-Methylhex-2-ene has two methyl groups on the same alkene carbon. In 1,1-dimethylcyclopropane both methyls sit on one ring carbon. Only 1,2-dimethylcyclohexane has one methyl and one hydrogen on each of two ring carbons, so the methyls can be on the same face or opposite faces.

Source: NEET 2025 (4 May), Code 45, Q58

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